Webb2024年2月28日 18:20. "如果数据接近正态分布,那么Shapiro-Wilk检验的P值就大于0.05". "如果数据接近正态分布,那么Shapiro-Wilk检验的P值就大于0.05" 难道不是0.1吗?. 一 … Webb14 apr. 2024 · First, the Shapiro–Wilk test was used to test the normality of the data, and the result was 0.97, p = 0.19 > 0.05, indicating that the sample in this study was normally distributed. Also, it was determined that the Levene test for homogeneity of variance was not violated ( F = 2.94, p = 0.06 > 0.05), indicating that the null hypothesis is valid and …
What is the consequence of a Shapiro-Wilk test-of-normality filter …
WebbHypotheses tests consider robust standard errors, since the Breusch-Pagan / Cook-Weisberg test indicated heteroscedasticity (p<0.01) and the dependent variables do not follow a normal distribution (based on the Shapiro-Wilk test for normal data, p<0.01). WebbShapiro-Wilk normality test data: my_data$len W = 0.96743, p-value = 0.1091 From the output, the p-value > 0.05 implying that the distribution of the data are not significantly different from normal distribution. In other words, we can assume the normality. Infos This analysis has been performed using R software (ver. 3.2.4). Enjoyed this article? citizens bank mortgage loan officer
Shapiro–Wilk正态性检验与R实现 - 知乎 - 知乎专栏
Webb30 okt. 2024 · In this example, we will be simply using the shapiro () function from the scipy.stats library to Conduct a Shapiro-Wilk test on the randomly generated data from … WebbQuestion. Use the Shapiro-Wilk test to check the normality assumption for the variable Starting_Sal. According to this test, does the variable Starting_Sal meet the normality … WebbThe problem is that the calculated p-value is affected by the size of the sample. Therefore, if you have a very small sample, your p-value may be much larger than 0.05, but if you have a very very large sample from the same population, your p-value may be smaller than 0.05. citizens bank mortgage insurance department